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Dear Friends,
I am sending this email to you because I know you are good in maths.
Now tell me where is the remaining 1 shilling from this story?

Three friends went to a hotel. The bill was Shs. 75/- Each one
contributed Shs.25/-. The waiter took the bill to the cashier.
The cashier was happy & decided to give them a discount of Shs.5/- &

asked the waiter to return them shs.5/-.

Now the waiter was confused on how to distribute Shs 5 among 3 persons?
He kept Shs 2 in his pocket & gave one Shilling to each one of the 3
persons.

So initially each one had contributed Shs.25. Now as they are given
1 Shilling back, their contribution reduces to Shs 24.
They all
contributed Shs. 24 -- that is 24x3=72 & 2 Shillings are in the
waiters pocket.

The total becomes 74. But they paid Shs. 75.

Where is the remaining 1 Shilling?

2007-03-16 03:30:56 · 5 answers · asked by candy 1 in Science & Mathematics Mathematics

5 answers

This rather old problem comes from a change in the rules of counting halfway through a calculation.

There are often many ways to resolve a math problem. Normally, using any one way should give the same result as any other way. After all, any well-defined problem should have only one answer.

In this problem, the apparent paradox comes from the fact that you begin the calcuations using one set of rules then, in the middle fo the solution, you change to a new set of rules.


Let us first take an outsider's view: We will look at five positions where the money is (three friends, the waiter, the cashier):

initial distribution=

25+25+25+0+0

the friends hand over the cash to the waiter
0+0+0+75+0
who hands it over to the cashier
0+0+0+0+75
The cashier gives 5 to the waiter
0+0+0+5+70
The waiter gives each friend 1:
1+1+1+2+70
This is the situation at the end: the total of money involved remains 75 throughout.

---

If you take the point of view of the three friends:
They gave 3*25 = 75.
They get 3*1 = 3 back.
They have paid: 75-3 = 72
As far as they are concerned, the hotel has 72. It makes no difference to them that the hotel's share is distributed as 2+70, it is still 72.

---

What the wording of the problem does is make it appear that the 2 is no longer part of the hotel share, that it is somehow to be added to the friends' payment (which already includes, unwillingly, a 2 shilling tip)

2007-03-16 03:54:17 · answer #1 · answered by Raymond 7 · 0 0

Their total contribution is 72 which includes the 2 shillings in the waiter's pocket. The total is 72, not 74.

Their contribution was 23.33x3=70 plus the 2 shillings in the waiter's pocket. Total is 72.

There is no missing shilling.

2007-03-16 10:42:22 · answer #2 · answered by Moon W 2 · 0 0

From the origional 75, the hotel has 70 the friends have 3 and the waiter has 2.

The 2 that the waiter has came from the 72 the friends paid. You are counting those 2 twice.

2007-03-16 10:37:16 · answer #3 · answered by John S 6 · 0 0

The paid 75 shilling - the five they got back which means they really paid 70 shilling

24*3 = 72

72 - 2 kept is 70

2007-03-16 10:36:17 · answer #4 · answered by Maverick 7 · 0 0

24 x 3 = 72

72 - 2 = 70

the 75 is irrelevant

2007-03-16 10:36:10 · answer #5 · answered by Hk 4 · 0 0

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