what is the discriminant and nature of roots of the given nunber x^2+12x+20=0?

Answer 1

x = - b ± √b² - 4ac / 2a

The discriminant determines whether the roots of a polynomial are real or not.

planetmath.org/encyclopedia/Discriminant.htm

- - - - - - - - - -s-

Answer 2

discriminant is b^2-4ac so your equation is 12^2-4(4)(9)=0 by way of fact the discriminant equals 0 there is one genuine root. If it equaled better than 0 the respond would have 2 genuine roots. If the respond would have been below 0 the respond would have been 2 complicated roots.

Answer 3

the discriminant is b^2-4ac = 64 which is perfect square

or you can easily factor to (x+2)(x+10) and get the roots -2, and -10

Answer 4

on the quadratic formula

x= (-b+/-(sqr rt.(b^2-4ac)))2a

the discriminant is

square root of b^2-4ac

a=1 b=12 c=20

subst

u willl arrive at

sqrt rt of 64= 8


the nature is real and equal

Answer 5

discriminant is b^2 - 4ac

which is 144-80 which is 64

if discriminant <0; no real roots
=0; two roots, but they are the same
>0; two real roots

in your case, two real roots

Answer 6

D=b^2-4ac
=144-80=64
x= (-b+-D^.5)/2a
=(-12+-8)/2=
so
x= -2 or-10
roots are real and distinct