English Deutsch Français Italiano Español Português 繁體中文 Bahasa Indonesia Tiếng Việt ภาษาไทย
All categories

I need to solve the equation and show that the answer checks. Please HELP if you can. Thanks!

2007-03-16 01:52:53 · 13 answers · asked by Deborah S 1 in Science & Mathematics Mathematics

13 answers

2x(7x+10) = 5x(x+1)
14x^2 + 20x = 5x^2 + 5x
9x^2 + 15x = 0
3x(3x + 5) = 0
3x = 0 or 3x + 5 = 0
x = 0 or x = -5/3

2007-03-16 01:56:23 · answer #1 · answered by tdw 4 · 1 0

2x(7x+10)=5x(x+1)
14x^2 + 20x = 5x^2 + 5x
9x^2 + 15x = 0
x(9x + 15) = 0
x = 0 and x = -15/9 = -5/3

To check the work:
x = 0
2x(7x+10)=5x(x+1)
2(0)(7*0 + 10) = 5(0)(0 + 1)
0(10) = 0(1)
0 = 0 TRUE

x = -5/3
2x(7x+10)=5x(x+1)
2(-5/3)(7 * -5/3 + 10) = 5(-5/3)(-5/3 + 1)
(-10/3)(-35/3 + 10) = (-25/3)(-5/3 + 1)
(-10/3)(-5/3) = (-25/3)(-2/3)
50/9 = 50/9 TRUE

2007-03-16 02:09:59 · answer #2 · answered by Mathematica 7 · 0 0

X = 0, or X = -5/3

2007-03-16 01:57:10 · answer #3 · answered by morningfoxnorth 6 · 1 0

here is how u solv it->
2x(7x+10) = 5x(x+1)
14x^2 + 20x = 5x^2 + 5x
9x^2 + 15x = 0
3x(3x + 5) = 0
3x = 0 or 3x + 5 = 0
x = 0 or x = -5/3

2007-03-16 02:46:34 · answer #4 · answered by Anonymous · 0 0

14x² + 20x = 5x² + 5x
9x² + 15x = 0
3x(3x + 5) = 0
x = 0, x = - 5/3
Check
for x = 0, lhs = rhs
for x = - 5/3:-
lhs = (- 10/3).(- 35/3+ 10)
lhs = (- 10/3).(- 5/3) = 50/9
rhs = (- 25/3).(-2/3) = 50/9
lhs = rhs so answer is correct

2007-03-16 02:21:16 · answer #5 · answered by Como 7 · 0 0

regrettably, I ignored the enrolling question. :( So i will answer besides, even in spite of the shown fact that I should not be graded. (yet once you ought to settle for one extra Ravenclaw i could be very grateful! Hahaha!) Charms: l. a. Barbe Cultivez - A spell derived from French, makes the sufferer improve an prolonged beard. the only thank you to opposite this spell is to apply a a Beard Shearing Draught. Shaving will in basic terms make it improve back even thicker. CoMC; i think of that this rule is preposterous. i think that upon Ministry Ruling (e.g XXXXX) the mystical Creatures could be achieved in basic terms in a humane way if discovered to be a extreme threat to Muggles and experienced wizards. i think of magical creatures could consistently be secure if discovered to no longer be a extreme threat. DADA: i think of, as Boggarts won't harm wizards, it could be a small, timid creature. because of the shown fact that Boggarts can handle many distinctive varieties, i think of that a Boggart might look fairly wispy and ghost like. Like a ghost crossed with a gnome, if it is smart. Herbology: Muggle legend says that there are 2 procedures a werewolf has been mentioned to handle finished Werewolf type. In finished moon, or whilst species of the plant Aconitum (additionally frequently going on as Wolfsbane, women's Bane, or Monkshood) are in finished bloom. This replaced into curiously first recorded in a 1941 Muggle action picture, entitled 'The Wolf guy'. even in spite of the shown fact that it extremely is asserted to have been extra Hollywood than history, and maximum folklore thoughts say that the technique is involuntary and each so often no longer even everlasting. Werewolf existance is frequently pushed aside as a figment of the mind's eye by muggle scientists, and maximum Muggles tend to have self assurance that Werewolves are actually not certainly real.

2016-10-02 05:27:11 · answer #6 · answered by ? 4 · 0 0

x=0 or x= -5/3

2007-03-16 02:58:54 · answer #7 · answered by S . Sushmita 2 · 0 1

x=4

2007-03-16 02:05:40 · answer #8 · answered by Karl E 1 · 0 2

2x(7x+10)=5x(x+1)
divide both sides by x we get,

2(7x+10)=5(x+1)

open the brackets on both sides

14x+20=5x+5

re arrange the eqn

14x-5x=5-20

9x= - 15

so

x= - 15/9

is the solution

2007-03-16 02:05:39 · answer #9 · answered by PUNJABI ROCKS 2 · 0 1

14x^2+20x=5x^2+5x
9x^2+15x=0
3x(3x+5)=0
x=0 or x= -5/3

2007-03-16 01:58:05 · answer #10 · answered by Maths Rocks 4 · 1 0

fedest.com, questions and answers