hi........if the equation is like this
x+4x=2
2x-8y=4
is this equation still dependent eventhough it dont have the same sign??
can this equation can still be considered
2007-03-16 00:51:35 · 4 answers · asked by sunade g 1 in Science & Mathematics ➔ Mathematics
left side the sign changed, right side it did not.
( and was not zero )
the equations are independent.
that is : there is no number a such that when you multiply the first equation with a, it becomes the same as the second equation.
2007-03-16 00:59:39 · answer #1 · answered by gjmb1960 7 · 0⤊ 0⤋
It is possible that you meant the first equation to be x + 4y = 2. If so then doubling this gives 2x + 8y = 4. Adding this to the other equation gives 4x = 8 so x = 2 and y = 0. There is still no inconsistency.
2007-03-16 01:18:01 · answer #2 · answered by mathsmanretired 7 · 0⤊ 0⤋
in the first equation,we get
5x=2
x=2/5
in the second substitute the value of x
we get y as
-8y=16/5
y=-2/5
so they are consistant as they have a solution
2007-03-16 01:04:15 · answer #3 · answered by satwik 2 · 0⤊ 0⤋
since the ratio of the coefficients of x and y are not the same the equations are independent
mathematical condition for a1x+b1y+c1=0
and a2x+b2+c2=0 to have unique solution is a1/a2not equal to b1/b2
2007-03-16 01:05:00 · answer #4 · answered by raj 7 · 0⤊ 0⤋