4x^2y^3+16x^3y^4-8x^4y^5=?
2007-03-15 18:24:05 · 5 answers · asked by Anonymous in Education & Reference ➔ Homework Help
pull out 4x^2y^3
and get
4*x^2*y^3(1 + 4xy - 2x^2y^2)
2007-03-15 18:28:05 · answer #1 · answered by tom t 2 · 0⤊ 0⤋
Start by pulling out the largest single factor:
4x^2y^3(1 + 4xy - 2x^2y^2). We look for factors of the parenthesized expression, but it is prime, so we're done.
2007-03-15 18:32:47 · answer #2 · answered by Anonymous · 0⤊ 0⤋
4(x^2y^3) + 16(x^3y^4) - 8(x^4y^5) =
4 , [x^2y^3 + 4(x^3y^4) - 2(x^4y^5)]
2007-03-15 19:43:09 · answer #3 · answered by edward_otto@sbcglobal.net 5 · 0⤊ 0⤋
4x^2y^3(4xy-2x^2y^2+1)
2007-03-16 02:54:36 · answer #4 · answered by Dave aka Spider Monkey 7 · 0⤊ 0⤋
Take more IQ Test can help you to slove this problem ;-D
2007-03-15 18:28:10 · answer #5 · answered by tanlip 1 · 0⤊ 0⤋