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I don't really need the answer, just how you would figure it out:
one force of 60 N and a second of 30 N act on a point P, what is the magnitude of the resultant when the angle between them is 45 degrees, o degrees, and 180 degrees. thank you

2007-03-15 17:07:30 · 4 answers · asked by skybluu 2 in Science & Mathematics Physics

4 answers

since the forces are acting on a point, use the head to tail method.
30N and 60N with 45deg in b/n and the resultant, which will give you a triangle.
then use a trig to find the magnitudes.

2007-03-15 18:52:08 · answer #1 · answered by DPLP 3 · 0 0

You need to triangulate those as vectors. Thus 60N produces .707 x 60 + .707 x 30 = Resulatant combined in the same direction, The .707 is the cos 45 Or you can use 1, 1 and square root of 2 to do the same thing for the 45 degrees . You crank that out.

You would do the same thing for O degrees , they'd be additive, 60 +30 =90 and for 180 they'd be 60-30=30 in the 60 direction.

2007-03-15 17:40:26 · answer #2 · answered by James M 6 · 0 0

What are the instruments for the mass??? i am going to guess grams. So m =350g =0.35kg. If we take the %.'s initial speed as effective, the frictional stress should be taken as unfavourable a = F/m = 0.-40 2/0.35 = -a million.2m/s^2 The unfavourable signal is major. without it calculations may practice friction causing % to strengthen, in spite of the undeniable fact that it motives % to shrink). to discover distance, use v^2 = u^2 +2as, with v (very last speed) = 0 0 = 6.0^2 + 2(-a million.2)s s = 36/2.4 = 15m

2016-12-02 02:02:38 · answer #3 · answered by ? 4 · 0 0

You have to break them up into their vector components and add them up. Fortunately, only the first problem requires that you do that.

HTH ☺

Doug

2007-03-15 17:32:19 · answer #4 · answered by doug_donaghue 7 · 0 0

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