(CoCl2 + NaOH = CoOH + Cl2Na)
(CuCl2 + NaOH = CuOH + Cl2Na)
(FeCl3 + NaOH = FeOH + Cl3Na)
(NiCl2 + NaOH = NiOH + Cl2Na)
2007-03-15 15:18:18 · 6 answers · asked by Anonymous in Science & Mathematics ➔ Chemistry
No they are wrong. When you separate the compounds into their ionic components you should see that Co is +2 and Cl is -1. That is why Co can bond to 2 Cl. Na is in the 1st column of the periodic table and so is +1, OH is polyatomic and is -1 so 1Na bonds to 1OH.
I've always taught the "crossover" method to my students. The subscript of one component of the compound is the superscript of the other ion. But you have to watch out for subscripts that will cancel one another.
The first equation should have Co(OH)2 + NaCl as products. You'll need to balance the equation from there.
2007-03-15 15:24:07 · answer #1 · answered by Tiffany T 3 · 1⤊ 0⤋
No.
CoCl2 + 2 NaOH ---> Co(OH)2 + 2 NaCl
First, Chlorine is a negative ion, therefore it will be last. Next, cobalt (in this case) has a +2 charge and hyroxide is -1, so that is why you have two hydroxide ions,
#2:
No. Similare to the first question.
CuCl2 + 2 NaOH ---> Cu(OH)2 + 2 NaCl
#3: No.
FeCl3 + 3 NaOH ---> Fe(OH)3 + 3 NaCl
#4:
NiCl2 + 2 NaOH .---> Ni(OH)2 + 2 NaCl
Remember: if you have a alkali metal (like sodium) and a halogen (like chlorine), the formula will always have the metal first and the halogen second.
2007-03-15 22:30:11 · answer #2 · answered by Carpetman_1998 2 · 0⤊ 0⤋
Double replacement reactions dont involve any change of valence. In problem 1, colbalt chloride reacts with sodium hydroxide to form the less caustic cobalt hydroxide and sodium chloride.
The valances for the components: Co is +2, Cl -1,
Na is +1 and OH is -1. Since you have 2 Cl-1, you need 2 Na to balance it (your product is NaCl in all these examples). The 2 Na will provide 2 OH, but thats just what the Co needs.
Just follow that along for the other 3 problems; they are pretty much the same.
2007-03-15 22:30:57 · answer #3 · answered by cattbarf 7 · 0⤊ 0⤋
COCl2 + 2NaOH ====>CO(OH)2 + 2NaCl
CuCl2 + 2NaOH ====> Cu(OH)2 + 2NaCl
FeCl3 + 3NaOH =====> Fe(OH)3 +3NaCl
NiCl2 + 2NaOH ======> Ni(OH)2 + 2 NaCl
2007-03-15 22:26:16 · answer #4 · answered by smarties 6 · 0⤊ 0⤋
NOOOOO
Ur NaCl2 is wrong (just wrote the right one)
There's no NaCl3
Cu(OH)2
Fe(OH)3 is wrong (I just wrote the right one, now you have to balance it)
Ni(OH)2
Didn't look through everything but these caught my eye quickly.
2007-03-15 22:27:27 · answer #5 · answered by Natasha 3 · 0⤊ 0⤋
No.
CoCl2 + 2NaOH = Co(OH)2 + 2NaCl
etc.
2007-03-15 22:21:42 · answer #6 · answered by Diana 1 · 0⤊ 0⤋