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connected to a 2.4 kV (rms) 740 Hz line? ohms

(b) What will be the peak value of the current? A

2007-03-15 14:32:16 · 1 answers · asked by Jade m 1 in Science & Mathematics Physics

1 answers

Z=1/(jωC)=-j/(2π*740*0.03E-06)=-j7169.1 Ω

V-peak=2.4E6*√2=3.39E6

V=IZ; I=V/Z; I=3.39E6/-j7169.1=j473.4 A or 473.4 A 90 degrees shifted from voltage

2007-03-15 14:49:16 · answer #1 · answered by Rob M 4 · 1 0

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