Ignore resistance.
a.)Calculate the impedance of the coil.
kohms
b.)Calculate the rms current in the coil.
mA
2007-03-15 14:30:29 · 3 answers · asked by Jade m 1 in Science & Mathematics ➔ Physics
z=jωL=j2πfL=j2π*14E3*160E-3=j14.1 kΩ
v=iz=>i=v/z=120/j14.1 kΩ= -j8.53 mA
2007-03-15 14:53:58 · answer #1 · answered by Rob M 4 · 0⤊ 0⤋
The voltage around the inductor is 114.5 V rms and L = 0.seventy six Henry commencing with this equation: one hundred twenty = iR + j(XL)i one hundred twenty = (ninety)i + jwLi the place w = 2?f = 377 for f = 60 Hertz The impedance Z = R + j377L = ninety +j377L The resistor R and the XL of the inductor are at precise angles to one yet another V inductor = ?((one hundred twenty² - Vr²) = ?((one hundred twenty² - 36²) = 114.5 V rms XL = (114.5/36)ninety = 286 ohms yet XL = 377L so 377L = 286 L = 0.seventy six Henry
2016-12-19 06:26:25 · answer #2 · answered by ? 4 · 0⤊ 0⤋
7?
lol.
2007-03-15 14:32:39 · answer #3 · answered by Anonymous · 0⤊ 0⤋