the distance a spring stretches varies directly with the force applied to it. if a 6 pound weight stretches a spring a distance of 21 inches, how far will the spring stretch if a 10 pound weight is applied?
2007-03-15 13:16:10 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Physics
21 inches divided by 6 pounds = 3.5 inches of spring for each pound of weight
10 pounds times 3.5 inches = 35 inches
2007-03-15 13:27:33 · answer #1 · answered by Husker41 7 · 0⤊ 0⤋
If distance D is proportional to Force
multiplying the force by 10/6 will multiply the distance by 10/6
So distance = 210/6 inches
= 35 inches
(so long as your spring doesn't give out in the meantime)
2007-03-15 13:21:10 · answer #2 · answered by Orinoco 7 · 0⤊ 0⤋
F = k * x
First, find the spring constant, k
6 = k * 21
k = 6 / 21 = 2 / 7 (The units are lb/in)
Next, find the distance for 10 lb
F = k * x
10 = 2 / 7 * x
70 / 2 in = 35 in = x
2007-03-15 13:23:31 · answer #3 · answered by Boozer 4 · 0⤊ 0⤋
x/10 = 21/6
x = 35 inches
2007-03-15 13:45:52 · answer #4 · answered by Helmut 7 · 0⤊ 0⤋
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2016-10-18 11:57:51 · answer #5 · answered by shakita 4 · 0⤊ 0⤋