in proposed telesurgery application ???

Question

in a proposed telesurgery application the images will be transmitted at 2x10*8(10 Raised to the power 8) m/s over a round -trip distance of 900 km.the compression and decompression processes for the images will take a total of 22 ms for trip,and other sources of dalay amount to 9 ms for the round trip. what is the total round-trip dalay???

Answer 1

Converting the speed to km/sec,

1800km/(2*10^5) = 0.009 sec = 9.0mS, plus the additional 22 plus 9 mS equals a total roundtrip time of 40mS (aka, 1/25th of a second).

Pieceacake, huh?