When they say that the amount of energy in a given amount of matter can be found out by the equation E=mc^2, do they mean *just* the energy found in that mass of matter, or do they mean the energy that would be released by reaction with an equal mass of antimatter, and therefore the amount of energy found in double that mass (the mass of the matter plus the equivalent mass of antimatter that would take part in the reaction)?
2007-03-15 10:52:40 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Physics
The Energy of Complete Annihilation, Rest Mass In the Equation. For Total Annihilation Resulting In a Single Photon, hv=mc^2.
2007-03-15 10:59:00 · answer #1 · answered by Anonymous · 0⤊ 0⤋
Suppose one lb. of matter were converted into energy, E=hf. Were one lb. of antimatter to be converted into energy, E=hf by contact with ordinary matter, it seems as though it would be a doubling of energy of either the matter or antimatter. Am I missing something in the question?
2007-03-15 12:35:16 · answer #2 · answered by Anonymous · 0⤊ 0⤋
It's the amount of energy that would be released if just that amount of matter were converted to energy.
HTH ☺
Doug
2007-03-15 11:15:19 · answer #3 · answered by doug_donaghue 7 · 0⤊ 0⤋
m is mass of normal everyday matter in grams. c is the speed of light in cm / sec answer is grams*cm^2 /sce^2
Einstein never asid anytning about anti-matter in his general or special theory of relativity.
2007-03-15 10:58:38 · answer #4 · answered by Robert S 1 · 0⤊ 0⤋