Chemistry Help? balancing equations?

Question

does anyone know how to balance the following?:

a strip of lead (+2) metal with alumium nitrate
Potassium chromate with barium nitrate
Sulfuric acid with ammonium hydroxide
C2H6 burned at night

Answer 1

3Pb + 2Al(NO3)3 --> 3Pb(NO3)2 + 2Al
K2CrO3 + Ba(NO3)2 --> 2K(NO3) + Ba(CrO3)
H2SO4 + 2NH4OH --> 2H2O + (NH4)2SO4
2C2H6 +7O2 ---> 4CO2 + 6H2O

Answer 2

A)
Pb(II) + Al(NO3)(3)
Since "nitrate" is -1, and Al +3 and
there are 3 (NO3) for each Al in aluminum nitrate,
there needs to be 3Pb(II) and 6(NO3) to balance the reaction:

3Pb(II) + 2Al(NO3)(3) ---> 3Pb(NO3)2 + 2Al(III)

B)
K(2) (CrO4) + Ba(NO3)(2) ---> Ba(CrO4) + 2K(NO3)

by similar logic to A)

C)
H(2)SO(4) + 2NH(4)OH ---> (NH4)(2)SO(4) + 2H(2)O

D)
This describes a combustion reaction, where C(2)H(6) reacts with oxygen gas to produce carbon dioxide and water:

C(2)H(6) + O(2) ---> CO(2) + H(2)O

add a 2 to the CO(2):

C(2)H(6) + O(2) ---> 2CO(2) + H(2)O

add a 3 to the H(2)

C(2)H(6) + O(2) ---> 2CO(2) + 3H(2)O

then by balancing the O(2)
there are 7 O atoms on the right, so:

C(2)H(6) + 3.5 O(2) ---> 2CO(2) + 3H(2)O

finish by multiplying the whole equation by 2 to get whole number coefficients:

2C(2)H(6) + 7O(2) ---> 4CO(2) + 6H(2)O

Answer 3

3 Pb + 2 Al(NO3)3 --> 2 Al + 3 Pb(NO3)2

K2CrO4 + Ba(NO3)2 --> BaCrO4 + 2 KNO3

H2SO4 + 2 NH4OH --> 2 H2O + (NH4)2SO4

2 C2H6 + 7 O2 --> 4 CO2 + 6 H2O