but how much greater is it?
and how do you work it out?
2007-03-15 06:59:11 · 6 answers · asked by malibuisace 2 in Science & Mathematics ➔ Chemistry
also, if a buffer solution is prepared, and then the components were halved would the pH stay the same?
thankyou
2007-03-15 07:02:37 · update #1
As you know that pH = - log [H+] then,
[H+] = 10^(-pH)
when you have a solution with pH = 2 concentration of ions is:
[H+] = 10^-2
in the other hand, if pH = 7 then the concentration would be:
[H+] = 10^-7
Just remember that negative exponents means zeroes at the left of the last significant cipher:
10^-2 = 0.01
10^-7 = 0.0000001
Hence: 0.0000001< 0.01
It means that solution with pH has a higher concentration of a solution with pH = 7.
Second part: Buffer solutions does not change their pH because they are formed by the mixing of a weak acid and its conjugate base. These systems can support addition of acid or base and pH without a significant pH change because dissociation of these compounds yields low amounts of the conjugate acid or base (low Ka constant) and hence, equilibrium of the reaction is easily displaced by the conjugate side to the opposite side.
Hope it helps!
Good luck!
2007-03-15 07:07:31 · answer #1 · answered by CHESSLARUS 7 · 1⤊ 0⤋
The H+ concentration of a solution of pH 2 is 100,000 times greater than one of pH 7. Every 1 pH unit represents a factor of 10.
Buffer solutions don't change their pH at all when diluted.
2007-03-15 07:06:18 · answer #2 · answered by Gervald F 7 · 1⤊ 0⤋
Yes, the lower the pH, the more H+ ions there are.
pH = -log[H+] rearrange that by multiplying both sides by -1 to get
-pH = log[H+] rearrange that by taking the inverse log of both sides to get
inv log (-pH) = [H+] and plug in the numbers
inv log (-2) = [H+] which is .01 Molar H+
Do the same for the pH 7 and you get .0000001 or 1x10 to the negative 7th
So, there are 100000 times more H+ ions in the pH 2 solution.
2007-03-15 07:55:10 · answer #3 · answered by Michael G 1 · 1⤊ 0⤋
Yes, by five orders of magnitude!
pH = -log (H+)
so a solution with a pH of 2 has 10^-2 (or 0.01) M H+
likewise, a solution with pH of 7 has (H+) of 10^-7 (or 0.0000001) M
2007-03-15 07:05:10 · answer #4 · answered by ? 4 · 1⤊ 0⤋
[H+] = 10^-pH
so for the solution with a pH of 2
[H+] = 10^-2
for pH = 7
[H+] = 10^-7
2007-03-15 07:05:20 · answer #5 · answered by Jon R 2 · 1⤊ 0⤋
yes by 10^5
2007-03-15 10:16:36 · answer #6 · answered by SS4 7 · 1⤊ 0⤋