2007-03-15 06:10:01 · 4 answers · asked by daw2017 1 in Science & Mathematics ➔ Physics
final velocity = initial velocity (zero) plus acceleration (g) times time (given)
plug and chug.
2007-03-15 06:16:24 · answer #1 · answered by Anonymous · 0⤊ 0⤋
Acceleration due to gravity is about 32 feet per second squared. 6 squared is 36 and multiplying by 32 yields 1152 feet per second. BUT, here's the catch. This does not account for friction of the air so this would be true only in outer space. So the real answer depends on the shape and density of the stone, and it's interaction with the air. So there is not enough information given, but certainly it would be much slower than 1152 feet per second which is just about the speed of sound. Why do you ask?
2007-03-15 13:27:53 · answer #2 · answered by honey_dopainters 1 · 0⤊ 1⤋
Earth's gravity without any wind resistance pulls objects at a rate of 9.8m/s for each second it falls.....so by the time it reaches 6 seconds of free fall it would be at a rate of 58.8m/s
2007-03-15 13:18:58 · answer #3 · answered by Daniel K 1 · 1⤊ 0⤋
x=1/2 *g* t^2 +vo*t+xo
2007-03-15 13:33:58 · answer #4 · answered by shiva 3 · 0⤊ 1⤋