Find 2 consecutive numbers such that the smaller plus 4 times the larger is 39?

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Find 2 consecutive numbers such that the smaller plus 4 times the larger is 39?

2007-03-15 05:46:00 · 4 answers · asked by Pinada 3 in Education & Reference ➔ Homework Help

4 answers

Let numbers be x and x + 1
x + 4.(x + 1) = 39
5x + 4 = 39
5x = 35
x = 7
Numbers are 7 and 8

2007-03-15 05:52:27 · answer #1 · answered by Como 7 · 0⤊ 0⤋

You know two things:
the 2 numbers are consecutive, so larger(y) - smaller(x) = 1
and x + 4y = 39.

Lets solve for y first: y - x = 1, so y = 1 + x

now change the equation to read: x + 4(1+x) = 39 then solve for x
x + 4 + 4x = 39
5x = 35
x = 7, y = 8

2007-03-15 13:00:30 · answer #2 · answered by Schlump 3 · 0⤊ 0⤋

7 and 8

2007-03-15 12:51:37 · answer #3 · answered by Curiosity 7 · 0⤊ 0⤋

x-1 , +4x = 39
5x = 40
x=8
ans 7, 8

2007-03-15 12:54:01 · answer #4 · answered by Wonka 5 · 0⤊ 0⤋