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If the plates of the capacitor are moved further apart by means of insulating handles

(a) The charge on the capacitor increases.
(b) The voltage across the plates increases.
(c) The capacitance increases.
(d) The electrostatic energy stored in the capacitor decreases.

2007-03-15 05:45:29 · 5 answers · asked by MOKSHA 3 in Science & Mathematics Physics

5 answers

(a) The charge stays the same (stated implicitly)

(c) Capacitance goes like one over the distance

(b) The voltage is the charge over the capacitance. So if charge stays the same (a), and capacitance goes ?(see part b), voltage must go ?.

(d) Energy is one half the charge times the voltage. Charge stays the same (a) and voltage goes (?) see (b). Therefore energy must go (?)

Figure it in this order. Fill in the question marks using the equations I put and you'll see what the answer is.

2007-03-15 05:55:03 · answer #1 · answered by Anonymous · 0 0

If the plates are countless in section then the electrical powered container keeps to be a persevering with ( container = flux / section by way of fact the section hasn't replaced and the full electric flux hasn't replaced then the sphere keeps to be consistent) A is fake As there's a tension of appeal between the plates, it takes artwork to cut up the plates including potential B is authentic ability difference is artwork / can charge. yet artwork ( potential) is bigger no longer decrease C is fake and D could be fake too. The can charge has nowhere to bypass. It won't be in a position to be created or destroyed even with the undeniable fact that that's disconnected from each and every little thing. so E is fake.

2016-12-14 19:51:45 · answer #2 · answered by ? 4 · 0 0

b.

Can't be a. because of conservation of charge
Can't be c. because the capacitance is inversely proportional to distance of plates: C = eps0 *A/d
Can't be d. because of conservation of Energy.

W = 0.5 * C * V^2
if C goes down, V goes up

also... when the plates are at distance x, there is a certain electric field between them measured in Volts/meter. As you increase the distance the same charge exists creating the field, so as 'meters' go up, Volts go up.

.

2007-03-15 05:54:54 · answer #3 · answered by tlbs101 7 · 3 0

There will be no change in the charge.
But there will be a change in the voltage. it will decrease
as distance increases.
thus capacitance increases
ur ans is (c)

also the electrostatic energy decreases(a bit doubtful about that)

2007-03-15 05:52:43 · answer #4 · answered by Anonymous · 0 1

d

2007-03-15 05:48:34 · answer #5 · answered by computerguy103 6 · 0 1

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