You are sitting on the outer edge of a merry go round and you move in towards the center. What would happen to your rotational speed?
2007-03-15 05:22:37 · 8 answers · asked by santista 2 in Science & Mathematics ➔ Physics
It would increase, because by moving toward the centre, you would decrease the overall moment of inertia of the merry-go-round. To conserve momentum, the merry-go-round would spin faster.
This is why a figure skater can spin faster by drawing his arms to his side or spin slower by extending them.
2007-03-15 05:30:08 · answer #1 · answered by computerguy103 6 · 0⤊ 0⤋
Your rotational speed remains constant no matter where on the merry go round you sit. However as you move towards the center your linear (tangential) speed decreases.
2007-03-15 05:35:55 · answer #2 · answered by Anonymous · 0⤊ 0⤋
The outer edge of a revolving circle has to go a certain speed to cover a certain distance in a certain time. If you move from the outer edge to the center, your forward spinning velocity slows down because you have a smaller distance to cover in the same amount of time. This why you have trouble keeping your balance when you do this.
2007-03-15 05:27:32 · answer #3 · answered by orion_1812@yahoo.com 6 · 1⤊ 1⤋
If the diameter is 18m, then a million/2 of that would desire to be the radius, so R=9m the frequency is 8.4/min, so divide that via 60 seconds, and you get a frequency of 0.14 revs consistent with 2nd. you will possibly be able to desire to locate the era, that's the time taken for the merry-bypass-around to end one circle. it is chanced on via f=a million/T, the place T is era, and f is frequency. So, T = a million / f, which = a million/0.14 = 7.14 seconds. Now, you employ the equation V= distance / time the area of a circle is 2x pi x r so, distance = 2 x pi x 9 = fifty six.fifty 4 m enter it into the above equation, making use of T (era) as time, and you get speed = fifty six.fifty 4 / 7.14 = 7.91ms^-a million So, the fee is 7.ninety one ms -a million desire that helps : ) stable success!
2016-10-18 11:04:40 · answer #4 · answered by ? 4 · 0⤊ 0⤋
your rotational speed will run our of your pockets an hit ppl in the face all standing around the merry go round :)
i dont think theres anything very " merry " about those things anyways?:|
2007-03-15 05:44:43 · answer #5 · answered by Alyssa K 1 · 0⤊ 0⤋
Your rotational speed stays exactly the same
- but your tangential speed decreases as you are travelling less distance per revolution.
2007-03-15 05:35:19 · answer #6 · answered by Doctor Q 6 · 1⤊ 0⤋
If you are asking about rpm's it stayed the same. If your are asking about mph's it when down. You will travel a shorter distance in the same amount of time.
2007-03-15 05:31:32 · answer #7 · answered by Uncle Boo 3 · 0⤊ 0⤋
speed will decrease because the radius decreases.
2007-03-15 05:34:48 · answer #8 · answered by 7 · 0⤊ 0⤋