help me with th is please!?

Question

a baseball thrown at an angle of 60degrees above the horizontal strikes a building that is 18m away at at point that is 8m above the point from which it is thrown. ignore air resistance
a) find the magnitude of the initial velocity of the baseball( the velocity at which the baseball is thrown)
b) find the magnitude and direction of the velocity of the baseball just before it strikes the building.
c) draw x-t, y-t, Vx-t, and Vy-t graphs of the motion.

this is all of the given information

Answer 1

Not enough information. You give distance to target, but not time. Theoretically, the ball could be thrown at the speed of light with no arc, at a much slower speed with an arc, or any speed in between. There is no way to tell from the given information.

Answer 2

d = 18 m
h = 8 m
g = 9.8 m/s^2
a = 60 deg

Time in flight:
T = d / Vh = d / (V cos a)

Height after time T:
H(T) = Vv T - 1/2 g T^2 = V sin a T - 1/2 g T^2

Equation to solve:
H(T) = h

V sin a T - 1/2 g T^2 = h

V sin(a) d / (V cos(a)) - 1/2 g (d / (V cos(a)))^2 = h

d tan(a) - 1/2 g d^2 sec^2(a) / V^2 = h

d tan(a) - h = 1/2 g d^2 sec^2(a) / V^2

V^2 = 1/2 (g d^2 sec^2(a)) / (d tan(a) - h)


What an ugly answer, who composed this problem?