It depends on your data. I found this on the attached web site
Properties of the different central tendency measures:
1. The mean is the standard measure of central tendency in statistics. It is most frequently used.
2. The mean is not necessarily equal to any score in the data set
3. The mean is the most stable measure from sample to sample.
4. The mean is very influenced by Outliers -- That is, the mean will be strongly influenced by the presence of extreme scores.
5. The median is not sensitive to outliers.
6. The mean is based on all scores from the sample but the mode and the median are not.
7. The Mode is the least stable measure from sample to sample.
8. The median is the best measure of central tendency if the distribution is skewed.
2007-03-15 02:42:07
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answer #1
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answered by Anonymous
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I think it would be the median. The average would tell you just that, but you don't have a feel for how thin or fat the dogs are. The mode only gives you the most frequently occuring weight, but still no sense of what's on the ends. The median would tell you which weight is in the middle, so half the dogs would be below this number, and half above. You would get a feel for the two halves. You could get a few really fat dogs that would take the average up, but if the middle or median number is much lower, you would sense that the higher average is due to a few stuffed sausages.
2007-03-15 02:39:53
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answer #2
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answered by Anonymous
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In order to undersand this question you need to understand the differences between these measures of averageness.
The "mean" is the mathematical average. It's the one people are usually introduced first to in school, where a list of numbers (like dog weights) is summed up and then divided by the number of list items. It is the most commonly used.
Taking the same list of numbers, the mode is the number that appears most often.
The median is the number right in the middle, where half of the amounts are below it and half are above it.
When a population is distributed normally, as in the classic "bell curve" all these three numbers will either be the same or very close. For the answer to the dog weight problem, since the sample size of a single neighborhood would be small, you need to decide which of these methods of averaging a list of numbers would be least affected by the variation of your sample.
2007-03-15 02:42:28
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answer #3
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answered by datamonkey0031 2
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Your problem lies in the fact that whoever asked you this question does not properly understand the measures of central tendancy. As you have been told, each gives a slightly different description of the central tendancy - it is completely wrong to attempt to then introduce a value judgment and say which one of the three is the best!
2007-03-15 05:46:36
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answer #4
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answered by SteveK 5
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mode
2007-03-17 05:08:37
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answer #5
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answered by rsudarsanlic 4
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I believe the answer is all.
2007-03-15 02:32:04
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answer #6
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answered by lcritter55118 4
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are you trying to complete homework? or what?
2007-03-15 02:39:15
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answer #7
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answered by maverick 3
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