Ships A and B leave port together. For the next two hours, ship A travels at 20.0 mph in a direction 30.0 degrees west of north while the ship B travels 75.0 degrees east of north at 40.0 mph.
What is the distance between the two ships two hours after they depart?
What is the speed of ship A as seen by ship B?
2007-03-15 01:40:15 · 5 answers · asked by RelientKayers 4 in Science & Mathematics ➔ Physics
XA = 2 * 20 sin30 = 20.0 miles west
YA = 2 * 20 cos30 = 34.6 miles north
XB = 2 * 40 cos75 = 77.3 miles east
YB = 2 * 40 sin75 = 20.7 miles north
Distance difference = (97.3, 13.9) = 98.3 miles
The speed is just the distance divided by 2 hours: 49.2 mph
2007-03-15 01:55:47 · answer #1 · answered by gebobs 6 · 1⤊ 0⤋
South. i got here upon this via trial and mistake, yet enable us to think of that A is shifting north, B is shifting West and C is shifting south. consequently, an observer from B could see A to be shifting North East, and from C they could see B to be shifting North West. because A and C are shifting in direction of one yet another, from A, C will seem to be shifting south. desire you purely needed an answer regardless of the indisputable fact that, i can not provide you a undeniable-fireplace rationalization.. Edit: i assume the respond varies counting on the way you place the ships. in case you line them up with A on the backside, B interior the midsection and C on the right you get B, yet any different way and it won't artwork.
2016-12-19 05:52:59 · answer #2 · answered by ? 3 · 0⤊ 0⤋
distace after two hrs d = 20x2xsin30 + 40x 2xsin75
speed of A relative to B
Vab = 20cos(30+75)
2007-03-15 01:55:21 · answer #3 · answered by tuoidabuon 2 · 0⤊ 0⤋
50 m/s squared
2007-03-15 01:43:20 · answer #4 · answered by Anthony V 1 · 0⤊ 1⤋
E = ernies, a bar in new london, CT. Only formula ever needed!!!
2007-03-15 01:58:53 · answer #5 · answered by Anonymous · 0⤊ 3⤋