solve for x.
answer: 0.631
2007-03-15 01:21:50 · 8 answers · asked by steven 1 in Science & Mathematics ➔ Mathematics
3^x+10=2(3^x+1)
3^x+10=2*3^x+2
8=2*3^x-3^x
8=3^x
taking log to the base 3
log8=x
x=ln8/ln3
x=0.631
2007-03-15 01:27:29 · answer #1 · answered by Anonymous · 0⤊ 0⤋
3-3+3-3+3-3+3-3+3=0
0+0.631= 0.631
duh:)
2007-03-15 08:39:09 · answer #2 · answered by trampazoid 3 · 0⤊ 0⤋
3^x + 10 = 3^x + 3^x + 2 (subtract 3^x each side)
10 = 3^x + 2 (subtract 2 each side)
8 = 3^x
x = .631
2007-03-15 08:29:57 · answer #3 · answered by chemmie 4 · 0⤊ 0⤋
3^x+10=2(3^x+1)?
Sol:
3^x+10= 2.3^x+2
so..3^x=8
so..x=log8 to the base 3
2007-03-15 08:27:46 · answer #4 · answered by Div 2 · 0⤊ 0⤋
3^x = 2*3^x - 8
3^x=8
x = log(base 3) 8
2007-03-15 08:26:59 · answer #5 · answered by blighmaster 3 · 0⤊ 0⤋
x=2x-4/3, depending on the objective of x
2007-03-15 08:56:34 · answer #6 · answered by Sandrew 2 · 0⤊ 0⤋
3^(x) + 10 = 2.3^(x) + 2
8 = 3^(x)
x log 3 = log 8
x = log 8 / log 3
x = 1.89
2007-03-15 09:07:29 · answer #7 · answered by Como 7 · 0⤊ 0⤋
let z=3^x...
z+10=2(z+1)
z+10=2z+2
z+8=2z
8=z or z=8 so
3^x=8
log(3^x)=log8
xlog3=log8
x=(log3/log8)
:)
2007-03-15 08:35:22 · answer #8 · answered by mikedotcom 5 · 0⤊ 0⤋