solve for x.
answer -4 and 4
2007-03-15 01:03:43 · 8 answers · asked by steven 1 in Science & Mathematics ➔ Mathematics
Square both sides to get:
x^2-7 = 9
x^2 = 16
lxl = 4
2007-03-15 01:08:41 · answer #1 · answered by blighmaster 3 · 0⤊ 0⤋
squareroot ((x^2)-7) = 3.
Squaring both sides,
x^2 - 7 = 9
x^2 = 9+7 = 16
x = square root of 16 = 4 or -4, because both 4^2 and -4^2 = 16.
2007-03-15 01:08:44 · answer #2 · answered by beachblue99 4 · 0⤊ 0⤋
for midpoint, upload the ends and divide via 2. M(-6/2, 8/2, 3/2) = M(-3, 4, a million½) for distance, upload the squares of the modifications and take squareroot. d = ?( 8² + 2² + a million²) = ?sixty 9
2016-10-18 10:42:47 · answer #3 · answered by ? 4 · 0⤊ 0⤋
(√x² - 7)² = (3)²
x² - 7 = 9
x² - 7 + 7 = 9 + 7
x² = 16
√x² = ± √16
x = ± 4
- - - - - - - - - s-
2007-03-15 01:58:19 · answer #4 · answered by SAMUEL D 7 · 0⤊ 0⤋
√(x² - 7) = 3
x² - 7 = 9
x² = 16
x = ± 4
2007-03-15 02:15:46 · answer #5 · answered by Como 7 · 0⤊ 0⤋
sqrt(x^2-7)=3
=> x^2-7=9 [squaring both sides]
=> x^2=16
=>x=+-4 [square-rooting both sides]
2007-03-15 01:14:04 · answer #6 · answered by alpha 7 · 0⤊ 0⤋
(x^2-7)^2=3
square both sides
x^2-7=9
x^2-7+7=9+7
x^2=16
x=-4;4 yes
2007-03-15 03:08:24 · answer #7 · answered by Dave aka Spider Monkey 7 · 0⤊ 0⤋
Huh?
2007-03-15 01:09:52 · answer #8 · answered by jopescu 2 · 0⤊ 0⤋