derivative of f(x)^2= x^2-x?

2007-03-14 22:36:02 · 2 answers · asked by mhelle 1 in Science & Mathematics ➔ Mathematics

2f(x)f'(x) = 2x - 1

f'(x) = (2x - 1)/2f(x)

2007-03-14 22:41:47 · answer #1 · answered by Amit Y 5 · 0⤊ 0⤋

f(x)= sqrt(x^2-x) for x Îµ(-â, 0)U(1,+â)
f'(x)= (-1/2)*(x^2-x)^(-1/2)*(2x-1)
f'x=-(2x-1)/[2*sqrt(x^2-x)]

2007-03-15 05:51:23 · answer #2 · answered by djin 2 · 0⤊ 0⤋

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