derivatives of f(x)= 4x^-3?

2007-03-14 22:27:18 · 3 answers · asked by mhelle 1 in Science & Mathematics ➔ Mathematics

f(x) = 4x^-3
f'(x) = (4)(-3)x^(-3-1)
f'(x) = -12x^-4

2007-03-14 22:31:30 · answer #1 · answered by seah 7 · 2⤊ 0⤋

f(x) = 4x^-3

f'(x) = -3*4x^-3-1
f'(x) = -12x^-4

2007-03-14 23:03:47 · answer #2 · answered by bach 2 · 0⤊ 0⤋

seah and bach both are correct.

2007-03-14 23:23:34 · answer #3 · answered by Titan 4 · 0⤊ 0⤋

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