A troop of 17 monkeys store their bananas in eleven piles of equal size with twelfth pile of six left over.?

Question

cont. of word problem.
when they divide the bananas into 17 equal groups none remain. What is the smallest number of bananas they can have? use modulo in this problem.

Answer 1

The smallest number of bananas they can have is 17.
11x + 6 = 17x
6 = 6x
x=1

They have 11 piles with one banana per pile and the 12th pile has 6 bananas, that's a total of 17 bananas.

If they have 17 banana's then they can have 17 piles and each pile can have one banana.

Answer 2

17 bananas, 1 in each pile, 6 left overs in the 12th pile.

if you allow a pile to have 0 bananas
then 6 bananas is the smallest number

Answer 3

N=total number of bananas
N=a*11
N=b*12-6
N=c*17

N=multiply of(11,17)={187,374,....187*n}
N+6 multiply of 12 ={193, 380, ...}
N=187*6=1122 (66 bananas for every monkey)

Answer 4

Are the ten and a half armpits ten and a half or 21?