5 years ago lucky was 3times as old as lovely. 10 years later,lucky woul be twice as old as lovely.how old are

Question

they now? Couldn't fit my question.

Answer 1

x = lucky
y = lovely

x-5 = 3(y-5)
x+10 = 2(y +10)

x=3y-10
3y-10+10=2y + 20

y=20
x=50

Answer 2

Let the age of Lucky be 'a' and age of Lovely be 'b'
5 years ago Lucky was (a – 5)
5 years ago Lucky was (b – 5)
From first statement (a – 5) = 3 (b – 5)
or a – 5 = 3b – 15
or a = 3b – 10 or a – 3b = – 10 -----eq.1
10 years later Lucky was (a + 10)
10 years ago Lucky was (b + 10)
From second statement (a + 10) = 2 (b + 10)
or a + 10 = 2b + 20
or a – 2b = 10 ------- eq. 2
Subtracting eq. 2 from eq. 1
– b = – 20
or b = 20 putting value in eq. 2
a – 40 = 10
or a = 50
Answer Lucky = 50 years and Lovely = 20 years

Answer 3

let x be lucky's age and y be lovely's age presently.

so five years ago,

x - 5 = 3 (y -5)
x - 5 = 3y -15
x = 3y - 10

ten years later,
x + 10 = 2 ( y + 10)
x + 10 = 2y + 20
x = 2y + 10

since you see that x = 3y - 10 and x = 2y + 10, then,

3y - 10 = 2y + 10
3y = 2y + 20
y = 20

sub this value into x = 2y + 10

x = 2 (20) + 10
x = 50

so, Lucky is 50 and Lovely is 20 rite now....

Answer 4

let U = lucky's age 5 years ago and L = Lovely's age 5 years ago

Then

U = 3L

and

U + 10 = 2 * (L + 10)


To solve, we substitue

3L + 10 = 2L + 20
L = 10
U = 30

That was 5 years ago. Now (5 years in the future be careful!) L = 15 and U = 35.

Double check.

5 Years ago
30 is 3 times 10

10 Years later (5 years from now)

40 is 2 times 20.

Solved.

Answer 5

Lucky And Lovely

Answer 6

Lucky=x (years old now)
Lovely=y (years old now)
x-5=3(y-5); x-3y=-10 x-3y=-10
x+5=2(y+5); x-2y=5 /*(-1) -x+2y=-5
-y=-15=>y=15
x=35

Answer 7

let
lucky's present age=x
lovely's present age=y

x-5=3*(y-5)
3y-x=10 eq1
x+10=2*(y+10)
x-2y=10 eq2

solving eq1&eq2

x=50 & y= 20

now lucky is 50 years old & lovely is 20 years old

Answer 8

l 35
lo 15