"If n is a perfect square, then n is not the product of 2 and an odd number."
Remember that an odd number can be expressed in the form
n = 2k + 1 (for an integer k).
Let's try proving this by contradiction. Assume that n IS the product of 2 and an odd number. That is, assume
n = 2(2k + 1). Then
n = 4k + 2
Since n is a perfect square, it follows that sqrt(n) is an integer. Therefore, sqrt(4k + 2) is an integer. Factoring out a 4,
sqrt(4[k + 2/4])
Reducing
sqrt(4[k + 1/2])
Splitting up the square root into 2,
sqrt(4)sqrt(k + 1/2)
2sqrt(k + 1/2)
This means k + (1/2) is a perfect square. This is impossible (the square root of non-integers are non-integers), and this is a contradiction.
2007-03-14 18:51:14
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answer #1
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answered by Puggy 7
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Let n be a perfect square. The square root of n, call it q, is either even or odd.
If q is odd, then n is odd and obviously cannot be a product of two and any integer.
If q is even, then it has 2 as a factor; since n is equal to 2 squared, it has 2 as a factor at least twice. (That is, you can divide it by 2 at least twice). Therefore, when you divide n by two, you get another even number, not an odd number.
In neither case can n=2x, with x being an odd number.
2007-03-15 02:25:19
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answer #2
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answered by William S 3
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well, if n is a perfect square, it can be 0 1 4 9 16 ...
the product of 2 * odd number = x
if u want x to equal to n, then x has to also be a perfect square
since x is 2 times sumdin, the sumdin HAS to be 2 also, or else x wont be a perfect square, but 2 is not an odd number, thatz y n cant be product of 2 and an odd number
2007-03-15 01:45:10
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answer #3
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answered by wenzhengsf 3
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There are two cases. Let n = z^2.
- If n is odd, then it obviously is not the product of 2 with anything.
- If n is even, then z is even: it is the product of 2 and some number k, and n is 4k*2. For n to be the product of 2 and an odd number, 2k*2 would have to be odd, which it clearly is not.
2007-03-15 02:43:07
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answer #4
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answered by Anonymous
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If 2 is a factor of a perfect square, then there must be a matching 2 amongst the other factors, thus prohibiting the product of the other factors from being an odd number.
2007-03-15 02:04:15
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answer #5
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answered by Helmut 7
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