Please...
try to put the answer is Scientific notation...
thank you
2007-03-14 18:37:19 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Astronomy & Space
I just now got a semimajor axis of 3.8476E8 meters by solving Kepler's law in Newton's form assuming a combined mass of 6.0475E24 kg and a sidereal month of 27.321582 mean solar days.
2007-03-14 19:12:20 · answer #1 · answered by Anonymous · 0⤊ 1⤋
Am I doing your homework?
Okay...You didn't give me enough information because at perigee the distance to the Moon is the least and at apogee the distance to the Moon is the greatest. (Yes...It varies since the Moon orbits the Earth in an elliptical path.)
So what orbital postion are we asking for? Do you want the "average" distance? You will remain a C student until you get the gumption to do your own research.
2007-03-15 02:43:48 · answer #2 · answered by mr.gold 1 · 0⤊ 1⤋
Or how about 2.38 x 10^5 miles...on average. It varies by +/- 2.0 x 10^4 miles, approximately.
2007-03-15 01:57:43 · answer #3 · answered by Anonymous · 0⤊ 0⤋
3.84400 x 10^5 km
2007-03-15 01:45:07 · answer #4 · answered by Helmut 7 · 0⤊ 0⤋