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A gas at 25 deg C and amospheric pressure fills a cylinder. The gas is transferred to a new cylinder with three times the volume, afer wwhick the pressure is half the original pressure. What is the new temperature of the gas?

10000 cm^3 of 200 degC steam at a pressure of 20 atm is cooled until it condenses. What is the volume of the liquid water, in cm^3?

2007-03-14 18:10:41 · 2 answers · asked by Anonymous in Science & Mathematics Physics

but the answer for the second one is 92....

2007-03-14 18:46:46 · update #1

2 answers

P1V1/T1 = P2V2/T2
T2 = (P2/P1)(V2/V1)T1
T2 = (P1/2P1)(3V1/V1)298
T2 = 447°K = 174°C

P1V1/T1 = P2V2/T2
V2 = (20/1)(10,000)(473/293) = 322,866.9 cm^3 @ STP (theoretical)
m = 18*322,866.9/22,400
m = 259.4466 g
V ≈ 259.4466 cm^3

2007-03-14 18:40:45 · answer #1 · answered by Helmut 7 · 0 0

first:

P1V1/T1 = P2V2/T2
T2 = (P2/P1)(V2/V1)T1
T2 = (P1/2P1)(3V1/V1)298
T2 = 447°K = 174°C

second:

PV=nRT ==>
(20*10^5)*(10*10^-3)=n * 8.314 * 473
===>n~5.1
n=m/M ==> m=5.1 * 18=91.8
_Pwater=m/v ===> v=91.8~92

2007-03-15 12:52:38 · answer #2 · answered by shiva 3 · 0 0

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