It is found that a 3 N force aaplied parallel to an inclined plane of angle 20 degree on a block of mass?

Question

0.5 kg leads to an acceleration of 1 m/s up the incline. What is the coefficient of kinetic friction between block and incline?

Answer 1

sum of forces must equal .5kg*1m/s/s=.5N
let
f1=3N force applied
c=coefficient of friction
f2=force of friction=.5kg*9.8m/s/s*sin20*c
sum of forces
f1-f2=.5N=>f2=f1-.5N
1.676N*c=2.5N
c=2.5/1.676=1.49
10 pts. if i'm right...

Answer 2

The forces at the same time ought to stability adverse to gravity, that's 70N downward. outline your axes so as that x is up the ramp (35 levels from horizontal) and y is perpendicular to that (35 levels from vertical). Friction is only in the +x route and the traditional stress in the +y route. Gravity has an x portion of -70sin(35) and a y portion of -70cos(35) to save the block from sliding, those should be precisely balanced by ability of a frictional stress of 70sin(35) and a classic stress of 70cos(35).