Calculate the mass of water in 500.0 g of Copper II sulfate penahydrate+ show work?

Question

Also. Avg Deviation- % of Deviation Reported % (class)
28.9, 50.00, 47.19, 41.67, 34.38, 43.0, 52.38, 43.53, 63.33
QUICKLY I NEED IT QUICK

Answer 1

Copper II sulfate pentahydrate = CuSO4 · 5H2O

Step 1: Find the molar mass.
Cu = 63.546
S = 32.065
O = 16 * 9 = 144
H = 1 * 5 = 10
molar mass = 249.611 rounded to 250

Step 2: Given molar mass and mass of CuSO4 · 5H2O, find # of moles.
500 g CuSO4 · 5H2O / 250 g/mol = 2 moles

Step 3: Multiply the # of moles by the # of moles of water in CuSO4 · 5H2O, then by the molar mass.
2 moles * 5 H2O = 10 moles H2O
Molar mass of H2O = 18 g/mol (2 from H, 16 from O).
10 moles * 18 g/mol = 180 g H2O (solution!)