if kelvin temp of gas if tripled, & Volume is double, the new pressure will be?

Question

(choose)
A)1/6 of original pressure
B)2/3 of orignal pressure
C)3/2 of original pressure
D)5 X the original pressure

Answer 1

P= nRT/V
nR is constant so
P = T/V

P=3/2 *nR

C is the correct answer

Answer 2

Rearrange pV=nRT into V=nRT/p. If we now double the temperature, the quantity will double to boot. If we triple the rigidity, the the rest volume would be a 0.33 of what it initially become. Combining those 2 outcomes potential the quantity would be 2/3 of the unique volume.

Answer 3

P1V1/T1 = P2V2/T2

V2 = 2, T2 = 3

T2/V2 = P2

3/2

so C

Answer 4

I believe its C because its T1/V1=T2/V2