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A block of ice with mass 5.80 kg is initially at rest on a frictionless, horizontal surface. A worker then applies a horizontal force \vec{F} to it. As a result, the block moves along the x-axis such that its position as a function of time is given by x(t)= ( 0.204 m/s^2) t^{2}+ ( 1.98×10−2 m/s^3) t^{3}.

Known Values from previous problems:

velocity of the object at time t = 3.80 s.
2.41 m/s

magnitude of \vec{F} at time t = 3.80 s.
4.98 N

would appreciate answer and/or explanation.

2007-03-14 14:19:32 · 2 answers · asked by eric 2 in Science & Mathematics Physics

2 answers

Errrmmmm...... There doesn't seem to *be* any question hiding in here.

Doug

2007-03-14 14:49:38 · answer #1 · answered by doug_donaghue 7 · 0 2

How long are the strings ?what's the pliancy of the strings?Are they the two a similar?i'm fairly effective the string at 10 tiers could have 4% better stress on it variety of appears like a trick question to me.If the pliancy of the strings grow to be distinctive & the lenghts of the string weren't a similar,One string ought to be helping just about ninety% of the burden.I in all probability think of too plenty!there is much extra variables than the two one human beings comprehend.in case you had to get fairly precise you'de would desire to comprehend if the strings have been putting one east & one west then the rotation of the earth could have a minute consequence on the outcomes.

2016-09-30 22:43:54 · answer #2 · answered by ? 4 · 0 0

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