How do you find height of equilateral triangle??

Answer 1

if you have the length of the sides, cut the triangle in half making 2 right triangles, then use pythagorean theorum to find the side of the half of the triangle which would be the height when you put the triangle back together.

Answer 2

To find the height of an equilateral triangle , follow these steps:
1.) Place a line from the vertex to the base of the triangle forming two right triangles. This will also cut your base in half.
2.) Then use the Pythagreom (sp?) Theorm [ a^2+b^2=c^2] to find the length of that line, which is now the height.

For example, if your base is 6 and u place a line from the vertex of the triangle to the base, each segment of the base would equal 3. If the hypotenuse of the newly formed right triangle equals 5, then you do 3squared (9) + bsquared= 5squared(25). That would be 9 + bsquared = 25. 25-9 is equal 16. The square root of 16 equals 4, which would be the height of the triangle.

Answer 3

What information to you have? If you drop a straight line from the apex to the base, you have divided the triangle into two right triangles. If you know the length of any of the sides, you can use the formula a squared + b squared = c squared where "C" is the hypotenuse. Since you don't want the value of C, but rather the value of the long side, just solve for that instead of c squared. Remember that the value of the base is now only half as long because the dropped line divides it it half. Does that make any sense?

Answer 4

You're kidding, right?
Divide the triangle in two, which gives you 2 right triangles.
Formula of the area of a triangle is 1/2b*h.
If you know the value of the base(of the original equilateral triangle), divide that in half to find the base of one right triangle.
Use the pythagorean theorem to find the length of the
unknown value of the side of one triangle, the height.

Answer 5

Area of a triangle= multiply base x height, then divide by 2. If you are given the area and the base, you can solve for the height:

Formula: A=bh/2

1. Multiply both sides by 2
2. divide both sides by your base
3. h= A/b

Answer 6

when you draw a segment from the vertex to the sides, it divides the sides in half and the angle of the vertex.

Now you have a special triangle. 30-60-90

short leg=x
long leg = xsqr(3)
hypotenue = 2x

the height of the triangle is the long leg
hope this helps

Answer 7

What Catie said.

Answer 8

http://www.analyzemath.com/Geometry/triangle_problems.html

scroll down for the formula, plug in your numbers where they have theirs.

Answer 9

ask ur mum