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A mixture of red light (vacuum = 661 nm) and green light (vacuum = 551 nm) shines perpendicularly on a soap film (n = 1.35) that has air on either side. What is the minimum nonzero thickness of the film, so that destructive interference causes it to look red in reflected light?

2007-03-14 12:40:26 · 2 answers · asked by marinatedpickles 2 in Science & Mathematics Physics

2 answers

The film thickness must be 1/2 wavelength for destructive interference:
2(1.35)t = 551/2
t = 10.185 nm

2007-03-14 12:59:43 · answer #1 · answered by Helmut 7 · 1 0

You want to absorb the green light, which means that the round trip through the film must be some multiple of a half wavelength, or a quarter wave each way. The wavelength in the film is smaller than the vacuum wavelength by a factor of 1.35, so if you do the appropriate arithmetic, you'll get the answer.

2007-03-14 13:00:27 · answer #2 · answered by Anonymous · 0 1

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