I need help with my Algebra homework. Please help!?

Question

i need some help with algebra.
i need to know how to find the following:

1. For a right triangle, if a=6, and c=12, find the value of B.

2. A 24 ft flagpole is to be secured by a wire from the top of the pole to the stake imbedded in the ground. The stake is located 21 ft from the base of the pole.If x represents the length of the wire to the nearest 10th of a foot,find the value of X.

3.Find the distance between (-2,1) and (4,-7).

if you know the answer to any of these, please solve them. And please show work,and/or explain how to solve the problem so i can know how to do the others on my own. thanks alot.

Answer 1

1.c squared = a squared + b squared
b squared = c squared - a squared
b squared =12 squared - 6 squared
b squared =144 - 36
b squared = 108
b = the square root of 108
b = 10.39
2.x squared =24 squared + 21 squared
x = the square root of 1017 = 31.9 feet

Answer 2

On #1, you'd have to assume that C is the right angle. Usually a capital letter refers to the angle and a lower case refers to a side. So B would mean the measure of angle B which is between a and c. That makes cosB = a/c = 6/12 and cos(60) = 1/2 so B is 60 degrees. But if you meant the length of b which it probably is based on the other two questions, just do 12^2 - 6^2 = b^2

#2 is Pythagorean Theorem; 24^2 + 21^2 = x^2

# 3 is distance formula, d^2 = (4 - -2)^2 + (-7 - 1)^2

Answer 3

Alright i will do as many as i can:
1. For right triangles ALWAYS use Pythagorean Theorum (not a great speller :))
a2 + b2 = c2 (the 2 represents the number squared)
so, 6[2] + b[2] = 12[2]
36 + b[2] = 144
b[2] =108
b= the square root of 108
which simplifies to: 6root3 or 6square roots of 3 (can't make the sqaure root sign)

2. not so sure

3. d= (the sqaure root of) ---> (x1-x2)[2] + (y1-y2)[2]
(The y1 and y2 and x1 and x2 represent the two x and y coordinates. Make sure you use the same x and y coordinate from one point in the same space!)
d= the square root of ---- (-2 - 4) [2] + (1- -7)[2]
(Everything is still under a radical)
d= the square root of ---- 36+64
so d= the square root of 100
so d=10

Hope this helps!

Answer 4

-4c - 3c = 22 - 36 -7c = -14 c = 2 4g/14 - g/14 = 3/14 + 3/7 3g/14 = 3/14 + 6/14 = 9/14 3g = 9 g = 3 3r/4 = 5/6 - 2/3 3r/4 = 5/6 - 4/6 3r/4 = a million/6 9r/12 = 2/12 9r = 2 r = 2/9 6x = 25 + 86 = 111 x = 111/6 x = $18.50

Answer 5

for number 3 don't you use the distance formula? i'll just do it anyways.

^2=squared
so:
d= (-2-4)^2+(1+7)^2 [all under a square root sign]

d= 36+64 [still under square root]
d=100[under square root]

now take the square root of 100
which is 10
so the distance is 10

Answer 6

For number 1 use a^2 + b^2 = c^2

I believe number 2 is the same formula as number 1

And number 3 use the distance formula

Answer 7

1. 6(squared) + b(squared)=12(squared). 36+b(squared)=144. b(squared)=108. b=(square root of)108

2. *not sure how to do #2*

3. (square root of) (4-(negative)2)(squared) + ((negative)7-1(squared)). (square root of)16+64. (square root of)100= 10

hope this helps and doesnt confuse you!

Answer 8

1) use pythagarian theroem

2) draw a digram

l\
l..\
l...\
l.....\
l___\

use pythagarian theorem
a^2 + b^2 = c^2
24^2 + b^2 = c^2
solve for c


3) use distance formula
D = sqr [ (x1-x2)^2 + (y1-y2)^2 ]

D = sqr [ (-2-4)^2 + (1-(-7))^2 ]

now just solve

hope this helps

Answer 9

for the first 2, just remember a^2 + b^2 = c^2. c hypotenuse