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Calculate the quantity of heat energy needed to raise the temperature of a piece of aluminium.?
mass=3kg
temperature from 20degree celcius to150 degree celcius
specific heat capacity of aluminium=910 J kg-1 K-1

2007-03-14 11:34:33 · 4 answers · asked by lamide e 1 in Science & Mathematics Physics

4 answers

this is quite easy if you know how to do it.

Heat Energy = M S T
where M = Mass in Kg; S = Specific Heat Capacity of the substance; T = is the change in temperature in kelvin.

So 3 x 910 x 130 = 354900 J or 354.90 KJ

I have used Celsius as my change in temperature because it does not matter here as constant of 273.15 will be deducted from both when you find the difference.

Hope this helps and don't forget to vote for the answer!!.

2007-03-14 11:43:34 · answer #1 · answered by Anonymous · 1 1

Q=m*Cp (t2-t1)
For aluminium Cp = 910j/kg/)K
Q= 3*910*(150-20)
Q=2730*130=354900joules

2007-03-14 12:11:21 · answer #2 · answered by Anonymous · 0 0

h = mc(delta)t
= 3(910)(150-20)
= 2730(130)
= 354900 J

(delta)t is the change in t (temperature)
c is the specific heat capacity

2007-03-14 11:40:58 · answer #3 · answered by misterbean 2 · 0 0

∆T = 130°C (or K)

130 x 3 x 0.910 = 355kJ

2007-03-14 12:12:44 · answer #4 · answered by Norrie 7 · 0 0

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