The pH of pure water at some temperature is 5.73. What is the value of Kw at this temperature?

Answer 1

H2O <=> H+ +OH-

Kw=[H+][OH-]

since it is only water [H+]=[OH-]

thus

Kw=[H+]^2
but [H+]=10^-pH
so Kw=(10^-pH)^2= 10^-(2*pH) =10^-(2*5.73) =3.47*10^-12

Answer 2

a million: In organic water, [H+] = [OH-]. consequently, opposite calculate the pH on your [H+] = a million.ninety 5 x 10^-6 M. because [H+] = [OH-], [OH-] = a million.ninety 5 x 10^-6 besides. basically sq. this style to get your Kw. Now, My discern for Kw is 3.eighty x 10^12. because Kw is someplace around fifty one.3 x 10^-14 at one hundred C, i could say that this pattern of water is a few distance on the topic of the boiling ingredient of water for this question which, i'm not a chemistry important, yet i think of that may not possible. back, not sure. #3: Ka = [H+][NO2]/[HNO2]. Make an ICE table and it would yeild 4.50 x 10^-4 = x^2/0.33-x yet you may get rid of the "-x" because of the fact 0.33 and 0.33-x are very just about equivalent (they don't variety by employing lots and this shortcut will possibly not continuously artwork). So: 4.50 x 10^-4 = x^2/0.33 x = 0.012 so pH = a million.ninety one. in case you want to pass previous college, use the quadratic formulation and you get x = 0.01. in case you remedy for pH employing 0.01 u get a pH of two. a million.ninety one and a pair of are very just about equivalent. Whichever your instructor is seeking. based off of what I did right here, see in case you are able to decide #2 and #4.

Answer 3

Work out 10 to the power of -5.73 and then square it.