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A coil has an inductance of 0.35 H and a resistance of 35 . The coil is connected to a 6.0 V battery. After a long time elapses, the current in the coil is no longer changing.
(a) What is the current in the coil?
(b) What is the energy stored in the coil?
(c) What is the rate of energy dissipation in the coil?

Who ever answers these questions correctly first, gets best answer.

2007-03-14 06:53:41 · 2 answers · asked by David S 2 in Science & Mathematics Physics

2 answers

(a) I=V/R
I=6.0/35=170mA
(b) E = .5 L I^2
E=.5 x .35 x .170= 29.75 mJoules

(c) P= rate of energy dissipation
P=R I^2 =
P=35 (.17) ^2= 10.1 mW

I hope it helps

2007-03-14 06:57:52 · answer #1 · answered by Edward 7 · 1 0

OPen your book and look up the formulae.

2007-03-14 07:07:32 · answer #2 · answered by Gene 7 · 1 0

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