The intensity goes like the square of the cosine of the angles between them.
So take the arc cosine of the square root of 1/3.
0 degrees is full intensity. 90 degrees is none. 30 degrees is three quarters. 45 degrees is half. 60 degrees is a quarter. So a third is probably about 55 degrees.
Edit: oops--Alexander is correct. I forgot that the first sheet kills half the light.
So yeah, take the arc cosine of the square root of 2/3--thirty something degrees.
2007-03-14 05:08:06
·
answer #1
·
answered by Anonymous
·
0⤊
0⤋
The first polaroid eliminates 50% of unpolarized light.
The second one must eliminate 1 - cos²φ = 1/3,
cos²φ = 2/3
φ = 35.3 deg
2007-03-14 05:27:37
·
answer #2
·
answered by Alexander 6
·
0⤊
1⤋
If the situation at the moment is completely polarsied, then the angle to reduce it to 1/3 is 60 degrees.
Okay then sorry it's 54.74 degrees.
I di it off the top of my head last time ;o)
2007-03-14 05:07:10
·
answer #3
·
answered by Doctor Q 6
·
0⤊
1⤋
See if this helps :)
2007-03-14 05:07:25
·
answer #4
·
answered by Christi D 2
·
1⤊
0⤋
63 degrees.... lol I'm not sure though
2007-03-14 05:07:02
·
answer #5
·
answered by Williewill 2
·
0⤊
1⤋
Do your own homework! LOL
2007-03-14 05:05:41
·
answer #6
·
answered by Anonymous
·
1⤊
2⤋