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6 answers

The intensity goes like the square of the cosine of the angles between them.

So take the arc cosine of the square root of 1/3.

0 degrees is full intensity. 90 degrees is none. 30 degrees is three quarters. 45 degrees is half. 60 degrees is a quarter. So a third is probably about 55 degrees.

Edit: oops--Alexander is correct. I forgot that the first sheet kills half the light.

So yeah, take the arc cosine of the square root of 2/3--thirty something degrees.

2007-03-14 05:08:06 · answer #1 · answered by Anonymous · 0 0

The first polaroid eliminates 50% of unpolarized light.
The second one must eliminate 1 - cos²φ = 1/3,
cos²φ = 2/3

φ = 35.3 deg

2007-03-14 05:27:37 · answer #2 · answered by Alexander 6 · 0 1

If the situation at the moment is completely polarsied, then the angle to reduce it to 1/3 is 60 degrees.


Okay then sorry it's 54.74 degrees.
I di it off the top of my head last time ;o)

2007-03-14 05:07:10 · answer #3 · answered by Doctor Q 6 · 0 1

See if this helps :)

2007-03-14 05:07:25 · answer #4 · answered by Christi D 2 · 1 0

63 degrees.... lol I'm not sure though

2007-03-14 05:07:02 · answer #5 · answered by Williewill 2 · 0 1

Do your own homework! LOL

2007-03-14 05:05:41 · answer #6 · answered by Anonymous · 1 2

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