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m^2-9n^2

2007-03-14 03:03:33 · 3 answers · asked by kcdude 5 in Science & Mathematics Mathematics

3 answers

difference of two squares: a^2-b^2=(a+b)(a-b)

therefore: m^2-9n^2= (m+3n)(m-3n)

2007-03-14 03:12:19 · answer #1 · answered by Anonymous · 2 0

The hint to look for is that the number is a square - so the expression is simply the difference between two squares: m^2 - (3n)^2
The answer then follows simply: (m+3n)(m-3n)

2007-03-14 10:14:35 · answer #2 · answered by SteveK 5 · 0 0

(m-3n)(m+3n)

2007-03-14 10:11:56 · answer #3 · answered by gjmb1960 7 · 0 0

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