Janet invested $25,000, part at 5% and part at 2%. If the total interest at the end of the year is $980, how much did she invest at 5%?
2007-03-14 03:03:09 · 4 answers · asked by Michelle P 1 in Science & Mathematics ➔ Mathematics
|a + b = 25.000
|0.05a + 0.02b = 980
a = 25,000 - b
0,05(25,000 - b) + 0,02b = 980
1250 - 0.05b + 0.02b = 980
-0.03b = 980 - 1250
b = -270 : -0.03b =
b = 9000
a = 25.000 - 9000
a = 16.000
Answer: She invested at 5%, $ 16,000.
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2007-03-14 03:54:10 · answer #1 · answered by aeiou 7 · 0⤊ 0⤋
x +y = 25,000
.05*x + .02*y = 980
so 5x+2y=98,000
1st equation gives us y=25,000 - x so
5x + 2(25,000 - x)=98,000
3x = 48,000 x = 16,000
2007-03-14 03:13:00 · answer #2 · answered by blighmaster 3 · 0⤊ 0⤋
.05P + .02(25000-P) = 980
.05P + 500 - .02P = .03P + 500 = 980
.03P = 480
P = 16000
2007-03-14 03:07:40 · answer #3 · answered by fcas80 7 · 0⤊ 0⤋
$16000:
Let x= amount at 5%
y= amount at 2%
x+y = 25000
0.05x+0.02y = 980
5x+2y=98000
2x+2y=50000
-----------------
3x = 48000
x=16000
2007-03-14 03:16:44 · answer #4 · answered by Anonymous · 0⤊ 0⤋