The top row is 1. The second row is 1 1. Arrange these in an equilateral triangle. Now, to continue, each new row starts and ends with 1. Otherwise, to get any number in any row, just add the two numbers diagonally above to the left and to the right. You can also get the i-th number in the j-th row by calculating the combination of j items taken i at a time. If you know what factorials are, you can calculate the 20-th row by computing
20! / (0!20!), 20! / (1!19!), 20!/(2!18!), and so on. (By 20!, I mean 20 factorial.) If you're not sure what this means, just look up combinatorics on the Internet.
2007-03-14 03:18:23
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answer #2
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answered by Anonymous
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1⤊
0⤋
1
1 ,1
1,2,1
1,3,3,1
1,4,6,4,1
1,5,10,10,5,1
1,6,15,20,15,6,1
1,7,21,35,35,21,7,1
1,8,28,56,70,56,28,8,1
1,9,36,84,126,126,84,36,9,1
1,10,45,120,210,252,210,120,45,10,1
ok - enough - you get the idea
2007-03-14 03:08:32
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answer #4
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answered by blighmaster 3
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1⤋