what is the temperature of the steam if the water boils at 96 degrees?
2007-03-14 01:25:52 · 6 answers · asked by kuwee 2 in Science & Mathematics ➔ Physics
It would boil at 96 at a higher point of sea level, cause there the atmospheric pressure is less and bonds between molecules of water are more easily loosened and it becomes gas (steam).
And it's true that while it becomes gas, all the heat offered is used for the phase change, so temperature doesn't rise.
2007-03-14 01:42:43 · answer #1 · answered by Lilly26 3 · 0⤊ 0⤋
96 degrees. At a phase transformation, temperature remains constant.
Once, however, the water becomes steam, it can then increase in temperature.
2007-03-14 01:29:16 · answer #2 · answered by gebobs 6 · 0⤊ 0⤋
there is no steam at 96 degrees.. (celcius righT??)) (unless ure up a mountain or something??)
the temperature remains constant, becase the heat is being used to break the bonds, to change the water from liquid to a gas
2007-03-14 01:51:06 · answer #3 · answered by Shoobie 2 · 0⤊ 0⤋
that's right. phase change so temp is the same. i was thinking why it should boil only at 96 degrees...if that's celcius. anyway, maybe it's higher than sea level. i'm not sure if it's higher or lower. sorry.
2007-03-14 01:36:33 · answer #4 · answered by ieatreese88 2 · 0⤊ 0⤋
The question refers back to the dating between temperature and quantity. Temperature ought to be in absolute figures (ok). (°C + 273). The gas will boost so its density in kg/m³ will shrink. The formulation used is T1/T2 = V1/V2 This comes out as: T1 x V2 = T2 x V1 T1 = 273K; T2 = 376K V1 = 0.179L; V2 = ? V2 = T1 x V1 ÷ T2 V2 = 273 x 0.179 ÷ 376 V2 = 0.12997L = 0.13 kg/m³
2016-09-30 21:58:55 · answer #5 · answered by ? 4 · 0⤊ 0⤋
it's 96 ºC
2007-03-14 01:38:32 · answer #6 · answered by physicist 4 · 0⤊ 0⤋