If 2 Litres of hot water at 90 C is added to 4 Litres of cold water at 10 C , What is the final Temreture?

Answer 1

Check this guide

http://dbhs.wvusd.k12.ca.us/webdocs/Thermochem/MixingWater.html

Answer 2

Since the heat capacity of water is virtually constant

(2*90+4*10)/6=(180+40)/6=220/6=36.7°C

Answer 3

you can say that the energy lost by the hot water is given to the cold water
so fromula Q = mc(tf-ti)

Q lost by hot water when the final temperature is Tf

Ql = 2c (tf -90) and

Q received by cold water when the final temperature is Tf

Qc = 4c (tf -10)

you write that -Ql = Qc so
2c(90-tf) =4c(tf-10) dividing by 2c
90-tf = 2tf-20
3tf =110 tf =110/3 =36.7

Answer 4

using :heat lost by hot water =heat gained by cold water
if the final tempreture=x
then,heat lost by hot water =m*s*(90-x)
heat gained by cold water=m1*s*(x-10)
weight of water is directly proportional to its volume hence using volume directly,
2*s*(90-x)=4*s*(x-10)
90-x=2x-20
110=3x
hence,
final Temreture=36.66C

Answer 5

35 °C