So we are given W,A,I,T and will need to discover G,O,S,L,P.
Of all the possible numbers, I've starred the ones we've used, the rest we need to find:
1 2* 3 4* 5 6 7* 8* 9 0
SLO8
+ GO
---------
S2OP
Our rightmost colum is 8 + some number. It can't be 0 or else we would have an 8 at the bottom. Therefore we know we will carry at least a 1 over to the next column. Since the biggest thing we can add is our outstanding 9, we know we will carry over exactly a 1. We know the second column carries as well, since our L did not add up to L, and we know the carry must be a 1, since no two single digits added together (even with a one carry from the first column) can add up to 20. So we carried a 1 over to our L, which mean L must be 1, so that when we add our 1 carry we get 2.
S1O8
+ GO
---------
S2OP
In our second column, we already figured out that we have a carry of 1 from our first column, but notice that we add G (plus the one carry) to O and get O. The only way to get O back is if we add ten, because anything plus ten will give us the same digit, plus a one carry. If you think about it, nothing else added to O, whatever O is, could get you back to O. We can't make G equal to 10, but with our one carry from the first column, that would make G 9.
S1O8
+ 9O
---------
S2OP
Now let's look at the numbers we have left. Again, I've starred the ones we've used:
1* 2* 3 4* 5 6 7* 8* 9* 0
And the only letters we have left to find are S, O, and P, so we can tell one of our numbers won't be used.
In our last column, we add O to 8 and get P. If we try all of our possibilites for O, we notice only 5 can work, because 8+3 will give us a 1, which we've already used so can't use that for P, 8+6 will give us a 4, which is used, and 8+0 would leave us with an 8, but P is different from W. So the only possilbe choice is an O of 5, because 8+5 will give us a 3 (plus the one carry we knew we had), and 3 is still available, so we just knocked down two more.
S158
+ 95
--------
S253
This leaves us with only the S left, and the only possible numbers remaining are 6 and 0. Since they ask for a specific answer, it is safe to assume that it must be the 6, since we don't generally write our numbers with 0s at the beginning. So for our final answer we have:
6158
+ 95
--------
6253
So then, STOP = 6253.
--charlie
2007-03-13 22:36:32
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answer #1
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answered by chajadan 3
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We know that G,S,T,O,P do not equal 2,4 or 7
W (8) + O >10, since O+G = 10+O, so G=9
SLO8
+ 9O
--------
STOP
Now, T = L+1, so either L=0, T=1 or L=5 T=6, but the latter leaves no room for value of O, so
S0O8
+ 9O
--------
S1OP
Only digits left are 3,5,6 so STOP = 6153
2007-03-13 21:33:56
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answer #2
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answered by pjjuster 2
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