Math Problem?

Question

Could anyone help out with this math problem as it is for my son's homework and we can usually help him but this is a bit confusing. Any help would be appreciated.

If a boy leaves home at 8:20am and walks at a speed of 1.5Metres per second,
A mum leaves 10 minutes later travelling on a bike at 6 Metres per second.
Question: If D= Distance (m) and T= Time (s) from when mum leaves write an equation for the distance that the boys mum has travelleed. Write another equation for the distance that the boy has travelled.
Equate these formula's and then solve to find T. Then substitue T in one of hte original equations to find D.

even if anyone can give an idea of how to solve the problem or where to start.

Thanks

Answer 1

All of the answers given above are wrong or incomplete. Follow my system, it's easy and correct.

We know, speed = distance/time
for Mom, speed = 6 meters per second
or, 6 = D/T
or, D/T = 6
or, D = 6T.............................(1)
here, D is in meters and T is in seconds.

for the boy, he started 10 minutes earlier.
10 minutes = 10 x 60 seconds = 600 seconds
So for his case, time will be (T+600) seconds. The distance will be same as they both travelled the same distance.

so, speed = 1.5 = D/(T+600)
or, D/(T+600) = 1.5
or, D = 1.5(T+100)..........................................................(2)

From equation (1) and (2) we have,

6T = 1.5(T+600)
or, 6T = 1.5T + 900
or, 6T - 1.5T = 900
or, 4.5T = 900
or, T = 900/4.5
so, T = 200 seconds = 180 + 20 seconds =3 minutes 20seconds

So the required time is 3 minutes and 20 seconds after the mom leaves. (Ans.)

form equation (1)
D = 6T
or, D = 6 x 200 [ T = 200 seconds]
or, D = 1200 meter

So distance = 1200 meter (Ans.)

boy started at 8:20 am, mom started 10 minutes later meaning at
8:30am and it took her 3 minutes and 20 seconds. So the time on the clock will be 8:33 am and 20 seconds.

Hope this was helpful.

Answer 2

the guy/girl (cant remember) below me did the problem with a better explanation, plus they are right about the seconds conversion, I missed that!


Distance =Rate X Time or D=RT

so Mums equation is: D=6(T+10)
NOTE: there is a "+10" b/c she left 10 minutes after boy did.

Boys equation is: D=1.5(T)

EQUATE- D=6(T+10) or D=6T +60
D=1.5T

set them = to eachother and solve for D, the go back to your original equation, plug D in and solve for the T.

Answer 3

I believe you'll have to also convert 10 minutes to seconds, because you have everything else in units of meters per second. 10 minutes = 300 seconds.

So doing that...

d = vt
dboy = (1.5)t
dmom = 6(t - 300)

1.5t = 6(t - 300)
1.5t = 6t - 1800
1800 + 1.5t = 6t
1800 = 6t - 1.5t
1800 = 4.5t
t = 1800/4.5 = 400 s = 6.66 minutes.

Now, just substitute that into one of the two formulas. I'll do both just to prove to you that you get the same answer.

dboy = 1.5t
dmom = 6(t - 300)

dboy = (1.5 m/s)(400 s) = 600 m
dmom = 6 m/s * (400 s - 300 s) = 6(100) = 600 m.

Answer 4

Distance = speed x time. Follow the instructions.

Answer 5

boy - head start + time = mom 's distance

10 mins times son's rate times seconds PLUS mom's time (t) times son's rate times seconds EQUALS Mom's time times Mom's rate times seconds

(10 x 1.5 x 60) + (t x 1.5 x 60) = (t x 6 x 60)

900+ 90t = = 360t.....subtract 90 t from both sides

900 = 270t....divide both sides by 270

= time for Mom

substitute in mother's side t x 6 for distance

best of luck!

u can do it!

Answer 6

Dboy = 1.5(T) .......(1)
Dmom = 6(T-10)...(2)

assuming you want to know when they are together set them equal and solve for T.

Answer 7

just 2 help u out u should make a more descriptive title so more peepZ wil answer ur question

as for your question, sorry, I do not know the answer, for I am foolish