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An object is undergoing simple harmonic motion with period 1.200 s and amplitude 0.600 m. At t=0 the object is at x=0. How far is the object from the equilibrium position when t=0.480s? [[[hint the answer is .353 meters]]]

2007-03-13 18:29:36 · 2 answers · asked by Anonymous in Science & Mathematics Physics

2 answers

.6sin(2pi/1.2 t) in radians see if that works out

2007-03-13 18:46:47 · answer #1 · answered by John 5 · 0 0

If it's simple harmonic motion the equation for displacement is
s = .6sin(2πt/1.2) so
s = .6sin(2π*.48/1.2) = .6*.5878 = .3526

HTH ☺

Doug

2007-03-13 18:48:36 · answer #2 · answered by doug_donaghue 7 · 0 0

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