Calculate the pH of a .44M solution of NaOCl.?

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Calculate the pH of a .44M solution of NaOCl.?

2007-03-13 17:29:23 · 2 answers · asked by Anonymous in Science & Mathematics ➔ Chemistry

2 answers

Ka (HOCl) = 3.5 * 10^-8, so Kb (OCl-) = 2.86 * 10^-7.

Kb = [HOCl][OH-}/[OCl-]
2.86 *10^-7 = x^2/0.44-x x<<<<0.44, so it drops out of denominator

2.86*10^-7 = x^2/0.44
1.26*10^-7 = x^2
x = [OH-] = 3.55*10^-4
[H+] = 2.82*10^-11, pH = 10.55

2007-03-13 17:50:51 · answer #1 · answered by TheOnlyBeldin 7 · 0⤊ 0⤋

Got a Ka? Nocando without it

2007-03-14 00:36:34 · answer #2 · answered by cattbarf 7 · 0⤊ 1⤋